Skill Rack Daily Challenge Solution Date - 20/04/2019

Skill Rack

Daily Challenge Solution

Date : 20/04/2019

ProgramID- 8515

Area of N Objects

The program must accept the shape and dimensions of N objects as the input. The program must print the sum of the area of all the objects as the output. The shape can be square or rectangle.
Boundary Condition(s):
1 <= N <= 1000
Input Format:
The first line contains N.
The next N lines contain the shape followed by dimension(s) side for square and length and breadth for rectangle separated by a space.
Output Format:
The first line contains the sum of the area of all the objects.
Example Input/Output 1:
Input:
4
square 5
rectangle 4 2
rectangle 3 10
square 11
Output:
184
Explanation:
The first object is square it's area is 5*5 = 25. The total area is 25.
The second object is rectangle it's area is 4*2 = 8. The total area is 33.
The third object is rectangle it's area is 3*10 = 30. The total area is 63.
The fourth object is square it's area is 11*11 = 121. The total area is 184.
Example Input/Output 2:
Input:
6
square 25
rectangle 17 24
square 5
rectangle 40 12
square 34
square 48
Output:
4998

Solution :

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#include<stdio.h>

#include <stdlib.h>

int main()

{

    int n,ans,total=0;

    char s[20];

    scanf("%d",&n);

    for(int i=0;i<n;i++)

    {

        scanf("%s",s);

        if(s[0]=='s')

        {

            int a;

            scanf("%d",&a);

            ans=a*a;

        }

        else

        {

            int a,b;

            scanf("%d %d",&a,&b);

            ans=a*b;

        }

        total=total+ans;

    }

    printf("%d",total);

}

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